leetcode_lcp20_go_迅速公交

mp, cost, target) % mod}func dfs(inc int, dec int, jump int, cost int, cur int) int {if cur == 0 {return 0}if cur == 1 {return inc}if visited[cur]> 0 {return visited[cur]}res := cur * inc // 最坏的状况：全部都是+1for i := 0; i b {return b}return a}。

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